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1302132222133 is a prime number
BaseRepresentation
bin10010111100101101001…
…000001110100010110101
311121111000211111120010021
4102330231020032202311
5132313231322102013
62434105152325141
7163035023160421
oct22745510164265
94544024446107
101302132222133
1146225a769246
121904415437b1
1395a37a87842
1447048821b81
1523d11204a8d
hex12f2d20e8b5

1302132222133 has 2 divisors, whose sum is σ = 1302132222134. Its totient is φ = 1302132222132.

The previous prime is 1302132222109. The next prime is 1302132222187. The reversal of 1302132222133 is 3312222312031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1301337940644 + 794281489 = 1140762^2 + 28183^2 .

It is a cyclic number.

It is not a de Polignac number, because 1302132222133 - 25 = 1302132222101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1302132222098 and 1302132222107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302132922133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651066111066 + 651066111067.

It is an arithmetic number, because the mean of its divisors is an integer number (651066111067).

Almost surely, 21302132222133 is an apocalyptic number.

It is an amenable number.

1302132222133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302132222133 is an equidigital number, since it uses as much as digits as its factorization.

1302132222133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1302132222133 its reverse (3312222312031), we get a palindrome (4614354534164).

The spelling of 1302132222133 in words is "one trillion, three hundred two billion, one hundred thirty-two million, two hundred twenty-two thousand, one hundred thirty-three".