Base | Representation |
---|---|
bin | 10010111100101101001… |
… | …000100001110011100011 |
3 | 11121111000211122120100021 |
4 | 102330231020201303203 |
5 | 132313231332113102 |
6 | 2434105154134311 |
7 | 163035023636425 |
oct | 22745510416343 |
9 | 4544024576307 |
10 | 1302132301027 |
11 | 46225a812548 |
12 | 190441581397 |
13 | 95a37ab471c |
14 | 47048842815 |
15 | 23d1121d137 |
hex | 12f2d221ce3 |
1302132301027 has 2 divisors, whose sum is σ = 1302132301028. Its totient is φ = 1302132301026.
The previous prime is 1302132301009. The next prime is 1302132301049. The reversal of 1302132301027 is 7201032312031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302132301027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1302132300992 and 1302132301010.
It is not a weakly prime, because it can be changed into another prime (1302132305027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651066150513 + 651066150514.
It is an arithmetic number, because the mean of its divisors is an integer number (651066150514).
Almost surely, 21302132301027 is an apocalyptic number.
1302132301027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302132301027 is an equidigital number, since it uses as much as digits as its factorization.
1302132301027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1302132301027 its reverse (7201032312031), we get a palindrome (8503164613058).
The spelling of 1302132301027 in words is "one trillion, three hundred two billion, one hundred thirty-two million, three hundred one thousand, twenty-seven".
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