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130217149 is a prime number
BaseRepresentation
bin1111100001011…
…11010010111101
3100002000201100101
413300233102331
5231313422044
620531001101
73140553556
oct760572275
9302021311
10130217149
1167560087
1237739191
1320c9358a
141341932d
15b672cd4
hex7c2f4bd

130217149 has 2 divisors, whose sum is σ = 130217150. Its totient is φ = 130217148.

The previous prime is 130217147. The next prime is 130217167. The reversal of 130217149 is 941712031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118417924 + 11799225 = 10882^2 + 3435^2 .

It is a cyclic number.

It is not a de Polignac number, because 130217149 - 21 = 130217147 is a prime.

It is a super-3 number, since 3×1302171493 (a number of 25 digits) contains 333 as substring.

Together with 130217147, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130217147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65108574 + 65108575.

It is an arithmetic number, because the mean of its divisors is an integer number (65108575).

Almost surely, 2130217149 is an apocalyptic number.

It is an amenable number.

130217149 is a deficient number, since it is larger than the sum of its proper divisors (1).

130217149 is an equidigital number, since it uses as much as digits as its factorization.

130217149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 28.

The square root of 130217149 is about 11411.2728913123. The cubic root of 130217149 is about 506.8616046883.

The spelling of 130217149 in words is "one hundred thirty million, two hundred seventeen thousand, one hundred forty-nine".