1302201123101 has 2 divisors, whose sum is σ = 1302201123102. Its totient is φ = 1302201123100.

The previous prime is 1302201123079. The next prime is 1302201123103. The reversal of 1302201123101 is 1013211022031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1266747999001 + 35453124100 = 1125499^2 + 188290^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1302201123101 is a prime.

Together with 1302201123103, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1302201123101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302201123103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651100561550 + 651100561551.

It is an arithmetic number, because the mean of its divisors is an integer number (651100561551).

Almost surely, 2^{1302201123101} is an apocalyptic number.

It is an amenable number.

1302201123101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302201123101 is an equidigital number, since it uses as much as digits as its factorization.

1302201123101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1302201123101 its reverse (1013211022031), we get a palindrome (2315412145132).

The spelling of 1302201123101 in words is "one trillion, three hundred two billion, two hundred one million, one hundred twenty-three thousand, one hundred one".