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13022021303117 is a prime number
BaseRepresentation
bin1011110101111110110011…
…1101000011101101001101
31201002220010001110122010122
42331133230331003231031
53201323044423144432
643410122313314325
72512544553524321
oct275375475035515
951086101418118
1013022021303117
1141706765a6762
1215639087059a5
13735c820589a8
143303aa94d981
15178aecac2612
hexbd7ecf43b4d

13022021303117 has 2 divisors, whose sum is σ = 13022021303118. Its totient is φ = 13022021303116.

The previous prime is 13022021303051. The next prime is 13022021303119. The reversal of 13022021303117 is 71130312022031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12185782382596 + 836238920521 = 3490814^2 + 914461^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13022021303117 is a prime.

Together with 13022021303119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13022021303119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511010651558 + 6511010651559.

It is an arithmetic number, because the mean of its divisors is an integer number (6511010651559).

Almost surely, 213022021303117 is an apocalyptic number.

It is an amenable number.

13022021303117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022021303117 is an equidigital number, since it uses as much as digits as its factorization.

13022021303117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 13022021303117 its reverse (71130312022031), we get a palindrome (84152333325148).

The spelling of 13022021303117 in words is "thirteen trillion, twenty-two billion, twenty-one million, three hundred three thousand, one hundred seventeen".