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1302211013317 is a prime number
BaseRepresentation
bin10010111100110001110…
…100110010101011000101
311121111020022202120022021
4102330301310302223011
5132313412004411232
62434121045203141
7163040000660344
oct22746164625305
94544208676267
101302211013317
114622a0194225
12190463a004b1
1395a4b1b3946
1447055091b5b
1523d180ba397
hex12f31d32ac5

1302211013317 has 2 divisors, whose sum is σ = 1302211013318. Its totient is φ = 1302211013316.

The previous prime is 1302211013293. The next prime is 1302211013353. The reversal of 1302211013317 is 7133101122031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1226137650721 + 76073362596 = 1107311^2 + 275814^2 .

It is an emirp because it is prime and its reverse (7133101122031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1302211013317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1302211013291 and 1302211013300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302211013017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651105506658 + 651105506659.

It is an arithmetic number, because the mean of its divisors is an integer number (651105506659).

Almost surely, 21302211013317 is an apocalyptic number.

It is an amenable number.

1302211013317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302211013317 is an equidigital number, since it uses as much as digits as its factorization.

1302211013317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 1302211013317 its reverse (7133101122031), we get a palindrome (8435312135348).

The spelling of 1302211013317 in words is "one trillion, three hundred two billion, two hundred eleven million, thirteen thousand, three hundred seventeen".