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130222030391 is a prime number
BaseRepresentation
bin111100101000111010…
…1100111111000110111
3110110010101201120001122
41321101311213320313
54113143314433031
6135453450014155
712260010665165
oct1712165477067
9413111646048
10130222030391
1150254a39922
12212a311735b
13c383ba346b
146434b84235
1535c25c047b
hex1e51d67e37

130222030391 has 2 divisors, whose sum is σ = 130222030392. Its totient is φ = 130222030390.

The previous prime is 130222030369. The next prime is 130222030417. The reversal of 130222030391 is 193030222031.

It is an a-pointer prime, because the next prime (130222030417) can be obtained adding 130222030391 to its sum of digits (26).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130222030391 - 210 = 130222029367 is a prime.

It is a super-3 number, since 3×1302220303913 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 130222030391.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130222033391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65111015195 + 65111015196.

It is an arithmetic number, because the mean of its divisors is an integer number (65111015196).

Almost surely, 2130222030391 is an apocalyptic number.

130222030391 is a deficient number, since it is larger than the sum of its proper divisors (1).

130222030391 is an equidigital number, since it uses as much as digits as its factorization.

130222030391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 26.

The spelling of 130222030391 in words is "one hundred thirty billion, two hundred twenty-two million, thirty thousand, three hundred ninety-one".