Base | Representation |
---|---|
bin | 1011110101111111100000… |
… | …1100111001101110100111 |
3 | 1201002220121012112201201121 |
4 | 2331133320030321232213 |
5 | 3201323441230142202 |
6 | 43410153134034411 |
7 | 2512552334500303 |
oct | 275377014715647 |
9 | 51086535481647 |
10 | 13022210005927 |
11 | 41707630729a1 |
12 | 156395b948a07 |
13 | 735cb2188b65 |
14 | 3303c7a30d03 |
15 | 178b0e449537 |
hex | bd7f8339ba7 |
13022210005927 has 2 divisors, whose sum is σ = 13022210005928. Its totient is φ = 13022210005926.
The previous prime is 13022210005921. The next prime is 13022210005999. The reversal of 13022210005927 is 72950001222031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13022210005927 - 219 = 13022209481639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13022210005892 and 13022210005901.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13022210005921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511105002963 + 6511105002964.
It is an arithmetic number, because the mean of its divisors is an integer number (6511105002964).
Almost surely, 213022210005927 is an apocalyptic number.
13022210005927 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022210005927 is an equidigital number, since it uses as much as digits as its factorization.
13022210005927 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
Adding to 13022210005927 its reverse (72950001222031), we get a palindrome (85972211227958).
The spelling of 13022210005927 in words is "thirteen trillion, twenty-two billion, two hundred ten million, five thousand, nine hundred twenty-seven".
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