Base | Representation |
---|---|
bin | 10010111100110010011… |
… | …111010100100010110111 |
3 | 11121111021002201222120021 |
4 | 102330302133110202313 |
5 | 132313422333141403 |
6 | 2434122124150011 |
7 | 163040164513162 |
oct | 22746237244267 |
9 | 4544232658507 |
10 | 1302222162103 |
11 | 4622a65094a5 |
12 | 190467698307 |
13 | 95a505b8365 |
14 | 47056754ad9 |
15 | 23d1906d8bd |
hex | 12f327d48b7 |
1302222162103 has 2 divisors, whose sum is σ = 1302222162104. Its totient is φ = 1302222162102.
The previous prime is 1302222162047. The next prime is 1302222162119. The reversal of 1302222162103 is 3012612222031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302222162103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302222163103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651111081051 + 651111081052.
It is an arithmetic number, because the mean of its divisors is an integer number (651111081052).
Almost surely, 21302222162103 is an apocalyptic number.
1302222162103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302222162103 is an equidigital number, since it uses as much as digits as its factorization.
1302222162103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1302222162103 its reverse (3012612222031), we get a palindrome (4314834384134).
The spelling of 1302222162103 in words is "one trillion, three hundred two billion, two hundred twenty-two million, one hundred sixty-two thousand, one hundred three".
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