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13022301004859 is a prime number
BaseRepresentation
bin1011110101111111110110…
…1000000010010000111011
31201002220211112202221210102
42331133331220002100323
53201324133024123414
643410210144310015
72512554521123306
oct275377550022073
951086745687712
1013022301004859
1141707aa476823
12156398631230b
13735cc7c9a693
143303d5b5bb3d
15178b17421ede
hexbd7fda0243b

13022301004859 has 2 divisors, whose sum is σ = 13022301004860. Its totient is φ = 13022301004858.

The previous prime is 13022301004819. The next prime is 13022301004861. The reversal of 13022301004859 is 95840010322031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13022301004859 - 212 = 13022301000763 is a prime.

It is a super-2 number, since 2×130223010048592 (a number of 27 digits) contains 22 as substring.

Together with 13022301004861, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13022301004819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511150502429 + 6511150502430.

It is an arithmetic number, because the mean of its divisors is an integer number (6511150502430).

Almost surely, 213022301004859 is an apocalyptic number.

13022301004859 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022301004859 is an equidigital number, since it uses as much as digits as its factorization.

13022301004859 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 13022301004859 in words is "thirteen trillion, twenty-two billion, three hundred one million, four thousand, eight hundred fifty-nine".