Base | Representation |
---|---|
bin | 1011110101111111111101… |
… | …1010111000110010001111 |
3 | 1201002220220122102120211121 |
4 | 2331133333122320302033 |
5 | 3201324213231100331 |
6 | 43410213141501411 |
7 | 2512555335051043 |
oct | 275377732706217 |
9 | 51086818376747 |
10 | 13022331112591 |
11 | 4170815470149 |
12 | 1563994411867 |
13 | 7360012ac6c8 |
14 | 3303d9b58023 |
15 | 178b19dbcc11 |
hex | bd7ff6b8c8f |
13022331112591 has 2 divisors, whose sum is σ = 13022331112592. Its totient is φ = 13022331112590.
The previous prime is 13022331112561. The next prime is 13022331112601. The reversal of 13022331112591 is 19521113322031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13022331112591 - 213 = 13022331104399 is a prime.
It is a super-2 number, since 2×130223311125912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13022331112561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511165556295 + 6511165556296.
It is an arithmetic number, because the mean of its divisors is an integer number (6511165556296).
Almost surely, 213022331112591 is an apocalyptic number.
13022331112591 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022331112591 is an equidigital number, since it uses as much as digits as its factorization.
13022331112591 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 34.
The spelling of 13022331112591 in words is "thirteen trillion, twenty-two billion, three hundred thirty-one million, one hundred twelve thousand, five hundred ninety-one".
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