Base | Representation |
---|---|
bin | 111100101000111110… |
… | …1100100101010011101 |
3 | 110110010112122102200200 |
4 | 1321101331210222131 |
5 | 4113144333124313 |
6 | 135454002414113 |
7 | 12260034464625 |
oct | 1712175445235 |
9 | 413115572620 |
10 | 130224114333 |
11 | 50256132595 |
12 | 212a3961339 |
13 | c384452b71 |
14 | 6435167885 |
15 | 35c2882b73 |
hex | 1e51f64a9d |
130224114333 has 48 divisors (see below), whose sum is σ = 192697989120. Its totient is φ = 84714020352.
The previous prime is 130224114259. The next prime is 130224114337. The reversal of 130224114333 is 333411422031.
It is a happy number.
130224114333 is a `hidden beast` number, since 1 + 3 + 0 + 224 + 1 + 1 + 433 + 3 = 666.
It is not a de Polignac number, because 130224114333 - 213 = 130224106141 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130224114297 and 130224114306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130224114337) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 83852485 + ... + 83854037.
It is an arithmetic number, because the mean of its divisors is an integer number (4014541440).
Almost surely, 2130224114333 is an apocalyptic number.
It is an amenable number.
130224114333 is a deficient number, since it is larger than the sum of its proper divisors (62473874787).
130224114333 is a wasteful number, since it uses less digits than its factorization.
130224114333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2458 (or 2455 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 130224114333 its reverse (333411422031), we get a palindrome (463635536364).
The spelling of 130224114333 in words is "one hundred thirty billion, two hundred twenty-four million, one hundred fourteen thousand, three hundred thirty-three".
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