Base | Representation |
---|---|
bin | 1011110110000010011101… |
… | …0110110011010001110011 |
3 | 1201002222122100012000001212 |
4 | 2331200213112303101303 |
5 | 3201332101242130344 |
6 | 43410403434350335 |
7 | 2512611052105622 |
oct | 275404726632163 |
9 | 51088570160055 |
10 | 13023001130099 |
11 | 41710296a1224 |
12 | 1563b4088b3ab |
13 | 7360aa051a7c |
14 | 330460b296b9 |
15 | 178b58b1b79e |
hex | bd8275b3473 |
13023001130099 has 2 divisors, whose sum is σ = 13023001130100. Its totient is φ = 13023001130098.
The previous prime is 13023001130063. The next prime is 13023001130131. The reversal of 13023001130099 is 99003110032031.
It is an a-pointer prime, because the next prime (13023001130131) can be obtained adding 13023001130099 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13023001130099 - 220 = 13023000081523 is a prime.
It is a super-2 number, since 2×130230011300992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13023001330099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511500565049 + 6511500565050.
It is an arithmetic number, because the mean of its divisors is an integer number (6511500565050).
Almost surely, 213023001130099 is an apocalyptic number.
13023001130099 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023001130099 is an equidigital number, since it uses as much as digits as its factorization.
13023001130099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 32.
The spelling of 13023001130099 in words is "thirteen trillion, twenty-three billion, one million, one hundred thirty thousand, ninety-nine".
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