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13023112231231 is a prime number
BaseRepresentation
bin1011110110000010110111…
…1110100111100100111111
31201002222221002020112011121
42331200231332213210333
53201332313212344411
643410422443531411
72512613601334624
oct275405576474477
951088832215147
1013023112231231
114171086385143
121563b71b29b67
137360c708139b
143304717aa34b
15178b63765571
hexbd82dfa793f

13023112231231 has 2 divisors, whose sum is σ = 13023112231232. Its totient is φ = 13023112231230.

The previous prime is 13023112231223. The next prime is 13023112231247. The reversal of 13023112231231 is 13213221132031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13023112231231 - 23 = 13023112231223 is a prime.

It is a super-2 number, since 2×130231122312312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13023112231196 and 13023112231205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13023112231201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511556115615 + 6511556115616.

It is an arithmetic number, because the mean of its divisors is an integer number (6511556115616).

Almost surely, 213023112231231 is an apocalyptic number.

13023112231231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023112231231 is an equidigital number, since it uses as much as digits as its factorization.

13023112231231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13023112231231 its reverse (13213221132031), we get a palindrome (26236333363262).

The spelling of 13023112231231 in words is "thirteen trillion, twenty-three billion, one hundred twelve million, two hundred thirty-one thousand, two hundred thirty-one".