Base | Representation |
---|---|
bin | 1011110110000010111010… |
… | …0100110001011100010111 |
3 | 1201002222221210001200011121 |
4 | 2331200232210301130113 |
5 | 3201332323242424421 |
6 | 43410423442144411 |
7 | 2512614052342624 |
oct | 275405644613427 |
9 | 51088853050147 |
10 | 13023122233111 |
11 | 4171090a96761 |
12 | 1563b75352107 |
13 | 7360c9173a63 |
14 | 330472c5134b |
15 | 178b6458dd41 |
hex | bd82e931717 |
13023122233111 has 2 divisors, whose sum is σ = 13023122233112. Its totient is φ = 13023122233110.
The previous prime is 13023122233097. The next prime is 13023122233129. The reversal of 13023122233111 is 11133222132031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13023122233111 - 221 = 13023120135959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13023122231111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511561116555 + 6511561116556.
It is an arithmetic number, because the mean of its divisors is an integer number (6511561116556).
Almost surely, 213023122233111 is an apocalyptic number.
13023122233111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023122233111 is an equidigital number, since it uses as much as digits as its factorization.
13023122233111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13023122233111 its reverse (11133222132031), we get a palindrome (24156344365142).
The spelling of 13023122233111 in words is "thirteen trillion, twenty-three billion, one hundred twenty-two million, two hundred thirty-three thousand, one hundred eleven".
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