Search a number
-
+
1302313209941 is a prime number
BaseRepresentation
bin10010111100110111111…
…010101001000001010101
311121111111110001200201102
4102330313322221001111
5132314114140204231
62434135135435445
7163042351431602
oct22746772510125
94544443050642
101302313209941
11462342946047
12190492085b85
1395a66416213
14470648956a9
1523d22055acb
hex12f37ea9055

1302313209941 has 2 divisors, whose sum is σ = 1302313209942. Its totient is φ = 1302313209940.

The previous prime is 1302313209881. The next prime is 1302313210031. The reversal of 1302313209941 is 1499023132031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1298015883025 + 4297326916 = 1139305^2 + 65554^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1302313209941 is a prime.

It is a super-2 number, since 2×13023132099412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1302313209895 and 1302313209904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302313206941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651156604970 + 651156604971.

It is an arithmetic number, because the mean of its divisors is an integer number (651156604971).

Almost surely, 21302313209941 is an apocalyptic number.

It is an amenable number.

1302313209941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302313209941 is an equidigital number, since it uses as much as digits as its factorization.

1302313209941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 38.

The spelling of 1302313209941 in words is "one trillion, three hundred two billion, three hundred thirteen million, two hundred nine thousand, nine hundred forty-one".