13023214410251 has 2 divisors, whose sum is σ = 13023214410252. Its totient is φ = 13023214410250.

The previous prime is 13023214410169. The next prime is 13023214410253. The reversal of 13023214410251 is 15201441232031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13023214410251 - 2¹⁴ = 13023214393867 is a prime.

It is a super-2 number, since 2×13023214410251² (a number of 27 digits) contains 22 as substring.

Together with 13023214410253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13023214410253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511607205125 + 6511607205126.

It is an arithmetic number, because the mean of its divisors is an integer number (6511607205126).

Almost surely, 2^{13023214410251} is an apocalyptic number.

13023214410251 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023214410251 is an equidigital number, since it uses as much as digits as its factorization.

13023214410251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 13023214410251 its reverse (15201441232031), we get a palindrome (28224655642282).

The spelling of 13023214410251 in words is "thirteen trillion, twenty-three billion, two hundred fourteen million, four hundred ten thousand, two hundred fifty-one".