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130232212959077 is a prime number
BaseRepresentation
bin11101100111001000001100…
…110010101010111101100101
3122002010002002211122211210122
4131213020030302222331211
5114032211033004142302
61140551504103331325
736300652433246165
oct3547101462527545
9562102084584718
10130232212959077
1138550198083359
1212733a60750b45
135788aca587498
1424233b657a5a5
15100c98aa733a2
hex76720ccaaf65

130232212959077 has 2 divisors, whose sum is σ = 130232212959078. Its totient is φ = 130232212959076.

The previous prime is 130232212958993. The next prime is 130232212959109. The reversal of 130232212959077 is 770959212232031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69159332131681 + 61072880827396 = 8316209^2 + 7814914^2 .

It is an emirp because it is prime and its reverse (770959212232031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130232212959077 - 222 = 130232208764773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130232212959677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65116106479538 + 65116106479539.

It is an arithmetic number, because the mean of its divisors is an integer number (65116106479539).

Almost surely, 2130232212959077 is an apocalyptic number.

It is an amenable number.

130232212959077 is a deficient number, since it is larger than the sum of its proper divisors (1).

130232212959077 is an equidigital number, since it uses as much as digits as its factorization.

130232212959077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2857680, while the sum is 53.

The spelling of 130232212959077 in words is "one hundred thirty trillion, two hundred thirty-two billion, two hundred twelve million, nine hundred fifty-nine thousand, seventy-seven".