Base | Representation |
---|---|
bin | 10010111100111000111… |
… | …111010110000010001011 |
3 | 11121111112200221201000121 |
4 | 102330320333112002023 |
5 | 132314133243020412 |
6 | 2434141021444111 |
7 | 163042660502431 |
oct | 22747077260213 |
9 | 4544480851017 |
10 | 1302331220107 |
11 | 462352027385 |
12 | 190498110637 |
13 | 95a6a080a18 |
14 | 47067022d51 |
15 | 23d23912107 |
hex | 12f38fd608b |
1302331220107 has 2 divisors, whose sum is σ = 1302331220108. Its totient is φ = 1302331220106.
The previous prime is 1302331220101. The next prime is 1302331220119. The reversal of 1302331220107 is 7010221332031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302331220107 is a prime.
It is not a weakly prime, because it can be changed into another prime (1302331220101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651165610053 + 651165610054.
It is an arithmetic number, because the mean of its divisors is an integer number (651165610054).
Almost surely, 21302331220107 is an apocalyptic number.
1302331220107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302331220107 is an equidigital number, since it uses as much as digits as its factorization.
1302331220107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1302331220107 its reverse (7010221332031), we get a palindrome (8312552552138).
The spelling of 1302331220107 in words is "one trillion, three hundred two billion, three hundred thirty-one million, two hundred twenty thousand, one hundred seven".
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