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1302333300133 is a prime number
BaseRepresentation
bin10010111100111001000…
…111010001110110100101
311121111112211212101021121
4102330321013101312211
5132314134311101013
62434141134213541
7163043014254565
oct22747107216645
94544484771247
101302333300133
11462353218108
121904989542b1
1395a6a62b6c8
1447067404da5
1523d23bc358d
hex12f391d1da5

1302333300133 has 2 divisors, whose sum is σ = 1302333300134. Its totient is φ = 1302333300132.

The previous prime is 1302333300029. The next prime is 1302333300167. The reversal of 1302333300133 is 3310033332031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 805141906209 + 497191393924 = 897297^2 + 705118^2 .

It is a cyclic number.

It is not a de Polignac number, because 1302333300133 - 29 = 1302333299621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1302333300098 and 1302333300107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302333300193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651166650066 + 651166650067.

It is an arithmetic number, because the mean of its divisors is an integer number (651166650067).

Almost surely, 21302333300133 is an apocalyptic number.

It is an amenable number.

1302333300133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302333300133 is an equidigital number, since it uses as much as digits as its factorization.

1302333300133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4374, while the sum is 25.

Adding to 1302333300133 its reverse (3310033332031), we get a palindrome (4612366632164).

The spelling of 1302333300133 in words is "one trillion, three hundred two billion, three hundred thirty-three million, three hundred thousand, one hundred thirty-three".