Base | Representation |
---|---|
bin | 11101100111001010000000… |
… | …111011100000010111011111 |
3 | 122002010021010122001112012121 |
4 | 131213022000323200113133 |
5 | 114032224030311311111 |
6 | 1140552425310043411 |
7 | 36301051633063306 |
oct | 3547120073402737 |
9 | 562107118045177 |
10 | 130234161432031 |
11 | 38550aa7a26988 |
12 | 127343051a9567 |
13 | 578904b160367 |
14 | 242351d26143d |
15 | 100ca51b58871 |
hex | 767280ee05df |
130234161432031 has 2 divisors, whose sum is σ = 130234161432032. Its totient is φ = 130234161432030.
The previous prime is 130234161431999. The next prime is 130234161432043.
130234161432031 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 130234161432031 - 25 = 130234161431999 is a prime.
It is a super-2 number, since 2×1302341614320312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130234161432091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117080716015 + 65117080716016.
It is an arithmetic number, because the mean of its divisors is an integer number (65117080716016).
Almost surely, 2130234161432031 is an apocalyptic number.
130234161432031 is a deficient number, since it is larger than the sum of its proper divisors (1).
130234161432031 is an equidigital number, since it uses as much as digits as its factorization.
130234161432031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 34.
The spelling of 130234161432031 in words is "one hundred thirty trillion, two hundred thirty-four billion, one hundred sixty-one million, four hundred thirty-two thousand, thirty-one".
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