Base | Representation |
---|---|
bin | 10010111100111001101… |
… | …010000111010100011111 |
3 | 11121111120111001022220001 |
4 | 102330321222013110133 |
5 | 132314144130311111 |
6 | 2434142102035131 |
7 | 163043155010314 |
oct | 22747152072437 |
9 | 4544514038801 |
10 | 1302342432031 |
11 | 462358395033 |
12 | 19049ba18aa7 |
13 | 95a6c4a80b4 |
14 | 47068700d0b |
15 | 23d248c91c1 |
hex | 12f39a8751f |
1302342432031 has 2 divisors, whose sum is σ = 1302342432032. Its totient is φ = 1302342432030.
The previous prime is 1302342431963. The next prime is 1302342432047.
It is a happy number.
1302342432031 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1302342432031 - 27 = 1302342431903 is a prime.
It is a super-2 number, since 2×13023424320312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302342432331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651171216015 + 651171216016.
It is an arithmetic number, because the mean of its divisors is an integer number (651171216016).
Almost surely, 21302342432031 is an apocalyptic number.
1302342432031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302342432031 is an equidigital number, since it uses as much as digits as its factorization.
1302342432031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
The spelling of 1302342432031 in words is "one trillion, three hundred two billion, three hundred forty-two million, four hundred thirty-two thousand, thirty-one".
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