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130234313399941 is a prime number
BaseRepresentation
bin11101100111001010001001…
…111111001101111010000101
3122002010021112020000021222201
4131213022021333031322011
5114032224333212244231
61140552452335154501
736301055456560402
oct3547121177157205
9562107466007881
10130234313399941
11385510757926a3
1212734348075a31
13578907379abba
1424235354dd2a9
15100ca60176161
hex767289fcde85

130234313399941 has 2 divisors, whose sum is σ = 130234313399942. Its totient is φ = 130234313399940.

The previous prime is 130234313399899. The next prime is 130234313400007. The reversal of 130234313399941 is 149993313432031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89010337451841 + 41223975948100 = 9434529^2 + 6420590^2 .

It is a cyclic number.

It is not a de Polignac number, because 130234313399941 - 245 = 95049941311109 is a prime.

It is a super-2 number, since 2×1302343133999412 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130234313399741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117156699970 + 65117156699971.

It is an arithmetic number, because the mean of its divisors is an integer number (65117156699971).

Almost surely, 2130234313399941 is an apocalyptic number.

It is an amenable number.

130234313399941 is a deficient number, since it is larger than the sum of its proper divisors (1).

130234313399941 is an equidigital number, since it uses as much as digits as its factorization.

130234313399941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5668704, while the sum is 55.

The spelling of 130234313399941 in words is "one hundred thirty trillion, two hundred thirty-four billion, three hundred thirteen million, three hundred ninety-nine thousand, nine hundred forty-one".