Base | Representation |
---|---|
bin | 11101100111010010101001… |
… | …000010001010110101100011 |
3 | 122002011011001011120222222002 |
4 | 131213102221002022311203 |
5 | 114032402013043431313 |
6 | 1141001000355234215 |
7 | 36301530316243643 |
oct | 3547225102126543 |
9 | 562134034528862 |
10 | 130243424202083 |
11 | 38554a20583145 |
12 | 1273606b2a896b |
13 | 5789b961a469a |
14 | 2423b5b518523 |
15 | 100cde4e3d058 |
hex | 7674a908ad63 |
130243424202083 has 2 divisors, whose sum is σ = 130243424202084. Its totient is φ = 130243424202082.
The previous prime is 130243424201971. The next prime is 130243424202107. The reversal of 130243424202083 is 380202424342031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130243424202083 - 212 = 130243424197987 is a prime.
It is not a weakly prime, because it can be changed into another prime (130249424202083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65121712101041 + 65121712101042.
It is an arithmetic number, because the mean of its divisors is an integer number (65121712101042).
Almost surely, 2130243424202083 is an apocalyptic number.
130243424202083 is a deficient number, since it is larger than the sum of its proper divisors (1).
130243424202083 is an equidigital number, since it uses as much as digits as its factorization.
130243424202083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 221184, while the sum is 38.
The spelling of 130243424202083 in words is "one hundred thirty trillion, two hundred forty-three billion, four hundred twenty-four million, two hundred two thousand, eighty-three".
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