Base | Representation |
---|---|
bin | 11101100111010010101001… |
… | …000010001010110101111011 |
3 | 122002011011001011120222222222 |
4 | 131213102221002022311323 |
5 | 114032402013043431412 |
6 | 1141001000355234255 |
7 | 36301530316244006 |
oct | 3547225102126573 |
9 | 562134034528888 |
10 | 130243424202107 |
11 | 38554a20583167 |
12 | 1273606b2a898b |
13 | 5789b961a46b8 |
14 | 2423b5b51853d |
15 | 100cde4e3d072 |
hex | 7674a908ad7b |
130243424202107 has 2 divisors, whose sum is σ = 130243424202108. Its totient is φ = 130243424202106.
The previous prime is 130243424202083. The next prime is 130243424202113. The reversal of 130243424202107 is 701202424342031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130243424202107 - 216 = 130243424136571 is a prime.
It is not a weakly prime, because it can be changed into another prime (130243424202127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65121712101053 + 65121712101054.
It is an arithmetic number, because the mean of its divisors is an integer number (65121712101054).
Almost surely, 2130243424202107 is an apocalyptic number.
130243424202107 is a deficient number, since it is larger than the sum of its proper divisors (1).
130243424202107 is an equidigital number, since it uses as much as digits as its factorization.
130243424202107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 130243424202107 its reverse (701202424342031), we get a palindrome (831445848544138).
The spelling of 130243424202107 in words is "one hundred thirty trillion, two hundred forty-three billion, four hundred twenty-four million, two hundred two thousand, one hundred seven".
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