Base | Representation |
---|---|
bin | 111100101001100110… |
… | …1010000110010011111 |
3 | 110110011222221202112121 |
4 | 1321103031100302133 |
5 | 4113220210120242 |
6 | 135500030243411 |
7 | 12260410162015 |
oct | 1712315206237 |
9 | 413158852477 |
10 | 130245004447 |
11 | 50266a00648 |
12 | 212aa956567 |
13 | c38888848c |
14 | 6437c448b5 |
15 | 35c460c667 |
hex | 1e53350c9f |
130245004447 has 2 divisors, whose sum is σ = 130245004448. Its totient is φ = 130245004446.
The previous prime is 130245004403. The next prime is 130245004453. The reversal of 130245004447 is 744400542031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130245004447 - 27 = 130245004319 is a prime.
It is a super-2 number, since 2×1302450044472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130245004847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65122502223 + 65122502224.
It is an arithmetic number, because the mean of its divisors is an integer number (65122502224).
Almost surely, 2130245004447 is an apocalyptic number.
130245004447 is a deficient number, since it is larger than the sum of its proper divisors (1).
130245004447 is an equidigital number, since it uses as much as digits as its factorization.
130245004447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 53760, while the sum is 34.
Adding to 130245004447 its reverse (744400542031), we get a palindrome (874645546478).
The spelling of 130245004447 in words is "one hundred thirty billion, two hundred forty-five million, four thousand, four hundred forty-seven".
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