Base | Representation |
---|---|
bin | 11101101000000111101101… |
… | …101010111011001001011111 |
3 | 122002100121010122000021202101 |
4 | 131220013231222323021133 |
5 | 114034320220014430023 |
6 | 1141043103201305531 |
7 | 36305615431212643 |
oct | 3550075552731137 |
9 | 562317118007671 |
10 | 130300410311263 |
11 | 38577103772445 |
12 | 127451139352a7 |
13 | 57923783c580a |
14 | 24268059cac23 |
15 | 100e62cca61ad |
hex | 7681edabb25f |
130300410311263 has 2 divisors, whose sum is σ = 130300410311264. Its totient is φ = 130300410311262.
The previous prime is 130300410311261. The next prime is 130300410311327. The reversal of 130300410311263 is 362113014003031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130300410311263 - 21 = 130300410311261 is a prime.
Together with 130300410311261, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130300410311261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65150205155631 + 65150205155632.
It is an arithmetic number, because the mean of its divisors is an integer number (65150205155632).
Almost surely, 2130300410311263 is an apocalyptic number.
130300410311263 is a deficient number, since it is larger than the sum of its proper divisors (1).
130300410311263 is an equidigital number, since it uses as much as digits as its factorization.
130300410311263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 130300410311263 its reverse (362113014003031), we get a palindrome (492413424314294).
The spelling of 130300410311263 in words is "one hundred thirty trillion, three hundred billion, four hundred ten million, three hundred eleven thousand, two hundred sixty-three".
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