Base | Representation |
---|---|
bin | 1011110110011101010001… |
… | …1101000111001011001111 |
3 | 1201010200020001112011022111 |
4 | 2331213110131013023033 |
5 | 3201441322223211002 |
6 | 43413554043524451 |
7 | 2513254336221262 |
oct | 275472435071317 |
9 | 51120201464274 |
10 | 13030200210127 |
11 | 417409335a641 |
12 | 156540b829727 |
13 | 73698667c339 |
14 | 330944ca8cd9 |
15 | 178e2ab5c3d7 |
hex | bd9d47472cf |
13030200210127 has 2 divisors, whose sum is σ = 13030200210128. Its totient is φ = 13030200210126.
The previous prime is 13030200210059. The next prime is 13030200210161. The reversal of 13030200210127 is 72101200203031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13030200210127 is a prime.
It is a super-2 number, since 2×130302002101272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13030200210098 and 13030200210107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13030200217127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515100105063 + 6515100105064.
It is an arithmetic number, because the mean of its divisors is an integer number (6515100105064).
Almost surely, 213030200210127 is an apocalyptic number.
13030200210127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13030200210127 is an equidigital number, since it uses as much as digits as its factorization.
13030200210127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 13030200210127 its reverse (72101200203031), we get a palindrome (85131400413158).
The spelling of 13030200210127 in words is "thirteen trillion, thirty billion, two hundred million, two hundred ten thousand, one hundred twenty-seven".
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