Base | Representation |
---|---|
bin | 1011110110011101011001… |
… | …0010111100101101000111 |
3 | 1201010200022012122112120102 |
4 | 2331213112102330231013 |
5 | 3201441403130201411 |
6 | 43414001105554315 |
7 | 2513255162615012 |
oct | 275472622745507 |
9 | 51120265575512 |
10 | 13030231100231 |
11 | 41740a9838854 |
12 | 156541a04599b |
13 | 73698cba64c7 |
14 | 33094902a379 |
15 | 178e2d70ed3b |
hex | bd9d64bcb47 |
13030231100231 has 2 divisors, whose sum is σ = 13030231100232. Its totient is φ = 13030231100230.
The previous prime is 13030231100197. The next prime is 13030231100233. The reversal of 13030231100231 is 13200113203031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13030231100231 is a prime.
It is a super-2 number, since 2×130302311002312 (a number of 27 digits) contains 22 as substring.
Together with 13030231100233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13030231100233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515115550115 + 6515115550116.
It is an arithmetic number, because the mean of its divisors is an integer number (6515115550116).
Almost surely, 213030231100231 is an apocalyptic number.
13030231100231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13030231100231 is an equidigital number, since it uses as much as digits as its factorization.
13030231100231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 13030231100231 its reverse (13200113203031), we get a palindrome (26230344303262).
The spelling of 13030231100231 in words is "thirteen trillion, thirty billion, two hundred thirty-one million, one hundred thousand, two hundred thirty-one".
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