Base | Representation |
---|---|
bin | 111100101011010101… |
… | …0100011000011111111 |
3 | 110110100001002220110221 |
4 | 1321112222203003333 |
5 | 4113330032404434 |
6 | 135505501442211 |
7 | 12262013223346 |
oct | 1712652430377 |
9 | 413301086427 |
10 | 130303013119 |
11 | 502967213a4 |
12 | 21306270367 |
13 | c3978b8c36 |
14 | 6441824b5d |
15 | 35c976a2b4 |
hex | 1e56aa30ff |
130303013119 has 2 divisors, whose sum is σ = 130303013120. Its totient is φ = 130303013118.
The previous prime is 130303012997. The next prime is 130303013299. The reversal of 130303013119 is 911310303031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130303013119 - 227 = 130168795391 is a prime.
It is a super-3 number, since 3×1303030131193 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 130303013093 and 130303013102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130303014119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65151506559 + 65151506560.
It is an arithmetic number, because the mean of its divisors is an integer number (65151506560).
Almost surely, 2130303013119 is an apocalyptic number.
130303013119 is a deficient number, since it is larger than the sum of its proper divisors (1).
130303013119 is an equidigital number, since it uses as much as digits as its factorization.
130303013119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 25.
The spelling of 130303013119 in words is "one hundred thirty billion, three hundred three million, thirteen thousand, one hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •