Base | Representation |
---|---|
bin | 10010111101100111011… |
… | …111001010011001010101 |
3 | 11121120120001211112021021 |
4 | 102331213133022121111 |
5 | 132322232444003411 |
6 | 2434350245521141 |
7 | 163101212254612 |
oct | 22754737123125 |
9 | 4546501745237 |
10 | 1303111312981 |
11 | 462712400735 |
12 | 1906754131b1 |
13 | 95b6288383a |
14 | 470dc889509 |
15 | 23d6c155a71 |
hex | 12f677ca655 |
1303111312981 has 2 divisors, whose sum is σ = 1303111312982. Its totient is φ = 1303111312980.
The previous prime is 1303111312973. The next prime is 1303111313003. The reversal of 1303111312981 is 1892131113031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1154700684900 + 148410628081 = 1074570^2 + 385241^2 .
It is a cyclic number.
It is not a de Polignac number, because 1303111312981 - 23 = 1303111312973 is a prime.
It is a super-2 number, since 2×13031113129812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303111312681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651555656490 + 651555656491.
It is an arithmetic number, because the mean of its divisors is an integer number (651555656491).
Almost surely, 21303111312981 is an apocalyptic number.
It is an amenable number.
1303111312981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303111312981 is an equidigital number, since it uses as much as digits as its factorization.
1303111312981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 34.
The spelling of 1303111312981 in words is "one trillion, three hundred three billion, one hundred eleven million, three hundred twelve thousand, nine hundred eighty-one".
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