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130311211404342 = 23171277560896121
BaseRepresentation
bin11101101000010001110001…
…011101110100110000110110
3122002101122000101011122222210
4131220101301131310300312
5114040004330104414332
61141052051042234250
736306450204043143
oct3550216135646066
9562348011148883
10130311211404342
11385807466a4551
1212747229055986
1357933aa059557
14242714c2c13ca
15100ea61154ecc
hex768471774c36

130311211404342 has 16 divisors (see below), whose sum is σ = 275953153562352. Its totient is φ = 40881948675840.

The previous prime is 130311211404337. The next prime is 130311211404377. The reversal of 130311211404342 is 243404112113031.

It is a super-2 number, since 2×1303112114043422 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 638780447959 + ... + 638780448162.

It is an arithmetic number, because the mean of its divisors is an integer number (17247072097647).

Almost surely, 2130311211404342 is an apocalyptic number.

130311211404342 is an abundant number, since it is smaller than the sum of its proper divisors (145641942158010).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130311211404342 is a wasteful number, since it uses less digits than its factorization.

130311211404342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1277560896143.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 130311211404342 its reverse (243404112113031), we get a palindrome (373715323517373).

The spelling of 130311211404342 in words is "one hundred thirty trillion, three hundred eleven billion, two hundred eleven million, four hundred four thousand, three hundred forty-two".

Divisors: 1 2 3 6 17 34 51 102 1277560896121 2555121792242 3832682688363 7665365376726 21718535234057 43437070468114 65155605702171 130311211404342