1303121111020 has 24 divisors (see below), whose sum is σ = 2736585503568. Its totient is φ = 521242507200.

The previous prime is 1303121111003. The next prime is 1303121111041. The reversal of 1303121111020 is 201111213031.

It is a happy number.

It is a super-3 number, since 3×1303121111020³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1303121110985 and 1303121111003.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1714615 + ... + 2355025.

It is an arithmetic number, because the mean of its divisors is an integer number (114024395982).

Almost surely, 2^{1303121111020} is an apocalyptic number.

1303121111020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1303121111020 is an abundant number, since it is smaller than the sum of its proper divisors (1433464392548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1303121111020 is a wasteful number, since it uses less digits than its factorization.

1303121111020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 742161 (or 742159 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 1303121111020 its reverse (201111213031), we get a palindrome (1504232324051).

It can be divided in two parts, 1303121 and 111020, that added together give a palindrome (1414141).

The spelling of 1303121111020 in words is "one trillion, three hundred three billion, one hundred twenty-one million, one hundred eleven thousand, twenty".