Base | Representation |
---|---|
bin | 1011110110100001000010… |
… | …1101101111001100011110 |
3 | 1201010202211111212211111101 |
4 | 2331220100231233030132 |
5 | 3202000410031420220 |
6 | 43414242240543314 |
7 | 2513321363420401 |
oct | 275502055571436 |
9 | 51122744784441 |
10 | 13031211201310 |
11 | 4174562000245 |
12 | 1565652321b3a |
13 | 736ab7c67283 |
14 | 3309dd277d38 |
15 | 178e897b030a |
hex | bda10b6f31e |
13031211201310 has 32 divisors (see below), whose sum is σ = 24369155778240. Its totient is φ = 5011143852288.
The previous prime is 13031211201233. The next prime is 13031211201319. The reversal of 13031211201310 is 1310211213031.
It is a super-2 number, since 2×130312112013102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13031211201319) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96359922 + ... + 96495061.
It is an arithmetic number, because the mean of its divisors is an integer number (761536118070).
Almost surely, 213031211201310 is an apocalyptic number.
13031211201310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13031211201310 is a deficient number, since it is larger than the sum of its proper divisors (11337944576930).
13031211201310 is a wasteful number, since it uses less digits than its factorization.
13031211201310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192855252.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13031211201310 its reverse (1310211213031), we get a palindrome (14341422414341).
The spelling of 13031211201310 in words is "thirteen trillion, thirty-one billion, two hundred eleven million, two hundred one thousand, three hundred ten".
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