Base | Representation |
---|---|
bin | 1011110110100001000111… |
… | …1001010011010111010111 |
3 | 1201010202212220011020021022 |
4 | 2331220101321103113113 |
5 | 3202000430114312023 |
6 | 43414244225311355 |
7 | 2513322023662424 |
oct | 275502171232727 |
9 | 51122786136238 |
10 | 13031231010263 |
11 | 41745721aaa84 |
12 | 1565658a9555b |
13 | 736abc0b174b |
14 | 330a01b52d4b |
15 | 178e8b3c47c8 |
hex | bda11e535d7 |
13031231010263 has 2 divisors, whose sum is σ = 13031231010264. Its totient is φ = 13031231010262.
The previous prime is 13031231010191. The next prime is 13031231010293. The reversal of 13031231010263 is 36201013213031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13031231010263 - 210 = 13031231009239 is a prime.
It is a super-2 number, since 2×130312310102632 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13031231010293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515615505131 + 6515615505132.
It is an arithmetic number, because the mean of its divisors is an integer number (6515615505132).
Almost surely, 213031231010263 is an apocalyptic number.
13031231010263 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031231010263 is an equidigital number, since it uses as much as digits as its factorization.
13031231010263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 13031231010263 its reverse (36201013213031), we get a palindrome (49232244223294).
The spelling of 13031231010263 in words is "thirteen trillion, thirty-one billion, two hundred thirty-one million, ten thousand, two hundred sixty-three".
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