130314124421431 has 4 divisors (see below), whose sum is σ = 130316613141832. Its totient is φ = 130311635701032.

The previous prime is 130314124421413. The next prime is 130314124421471. The reversal of 130314124421431 is 134124421413031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130314124421431 - 2¹¹ = 130314124419383 is a prime.

It is a super-2 number, since 2×130314124421431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130314124421401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1244281656 + ... + 1244386381.

It is an arithmetic number, because the mean of its divisors is an integer number (32579153285458).

Almost surely, 2^{130314124421431} is an apocalyptic number.

130314124421431 is a deficient number, since it is larger than the sum of its proper divisors (2488720401).

130314124421431 is an equidigital number, since it uses as much as digits as its factorization.

130314124421431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2488720400.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 130314124421431 its reverse (134124421413031), we get a palindrome (264438545834462).

The spelling of 130314124421431 in words is "one hundred thirty trillion, three hundred fourteen billion, one hundred twenty-four million, four hundred twenty-one thousand, four hundred thirty-one".