130314124421471 has 2 divisors, whose sum is σ = 130314124421472. Its totient is φ = 130314124421470.

The previous prime is 130314124421413. The next prime is 130314124421477. The reversal of 130314124421471 is 174124421413031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130314124421471 - 2¹⁸ = 130314124159327 is a prime.

It is a super-3 number, since 3×130314124421471³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130314124421477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65157062210735 + 65157062210736.

It is an arithmetic number, because the mean of its divisors is an integer number (65157062210736).

Almost surely, 2^{130314124421471} is an apocalyptic number.

130314124421471 is a deficient number, since it is larger than the sum of its proper divisors (1).

130314124421471 is an equidigital number, since it uses as much as digits as its factorization.

130314124421471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 38.

The spelling of 130314124421471 in words is "one hundred thirty trillion, three hundred fourteen billion, one hundred twenty-four million, four hundred twenty-one thousand, four hundred seventy-one".