Base | Representation |
---|---|
bin | 11101101000010100011111… |
… | …000110000110100100111000 |
3 | 122002101220112101112021012122 |
4 | 131220110133012012210320 |
5 | 114040031311322441212 |
6 | 1141053252102300412 |
7 | 36306612325220300 |
oct | 3550243706064470 |
9 | 562356471467178 |
10 | 130314124421432 |
11 | 38581a00a54396 |
12 | 12747900727708 |
13 | 57937527071c3 |
14 | 2427347124600 |
15 | 100eb81c66272 |
hex | 76851f186938 |
130314124421432 has 48 divisors (see below), whose sum is σ = 296588934484560. Its totient is φ = 53420696964096.
The previous prime is 130314124421413. The next prime is 130314124421471. The reversal of 130314124421432 is 234124421413031.
It is a junction number, because it is equal to n+sod(n) for n = 130314124421392 and 130314124421401.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7226816873 + ... + 7226834904.
It is an arithmetic number, because the mean of its divisors is an integer number (6178936135095).
Almost surely, 2130314124421432 is an apocalyptic number.
It is an amenable number.
130314124421432 is an abundant number, since it is smaller than the sum of its proper divisors (166274810063128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130314124421432 is a wasteful number, since it uses less digits than its factorization.
130314124421432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14453651820 (or 14453651809 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 130314124421432 its reverse (234124421413031), we get a palindrome (364438545834463).
The spelling of 130314124421432 in words is "one hundred thirty trillion, three hundred fourteen billion, one hundred twenty-four million, four hundred twenty-one thousand, four hundred thirty-two".
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