Base | Representation |
---|---|
bin | 1011110110100100000001… |
… | …1100001010010101000111 |
3 | 1201010211220022112112220222 |
4 | 2331221000130022111013 |
5 | 3202004030021301411 |
6 | 43414453522414555 |
7 | 2513350255304522 |
oct | 275510034122507 |
9 | 51124808475828 |
10 | 13032011900231 |
11 | 4174932a79195 |
12 | 156583650145b |
13 | 736bb4b0330c |
14 | 330a77745bb9 |
15 | 178ed4c244db |
hex | bda4070a547 |
13032011900231 has 2 divisors, whose sum is σ = 13032011900232. Its totient is φ = 13032011900230.
The previous prime is 13032011900203. The next prime is 13032011900261. The reversal of 13032011900231 is 13200911023031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13032011900231 is a prime.
It is a super-2 number, since 2×130320119002312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13032011900231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13032011900261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516005950115 + 6516005950116.
It is an arithmetic number, because the mean of its divisors is an integer number (6516005950116).
Almost surely, 213032011900231 is an apocalyptic number.
13032011900231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032011900231 is an equidigital number, since it uses as much as digits as its factorization.
13032011900231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 26.
Adding to 13032011900231 its reverse (13200911023031), we get a palindrome (26232922923262).
The spelling of 13032011900231 in words is "thirteen trillion, thirty-two billion, eleven million, nine hundred thousand, two hundred thirty-one".
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