130320133141181 has 2 divisors, whose sum is σ = 130320133141182. Its totient is φ = 130320133141180.

The previous prime is 130320133141103. The next prime is 130320133141217. The reversal of 130320133141181 is 181141331023031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66487879080100 + 63832254061081 = 8154010^2 + 7989509^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130320133141181 is a prime.

It is a super-2 number, since 2×130320133141181² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130320133141381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65160066570590 + 65160066570591.

It is an arithmetic number, because the mean of its divisors is an integer number (65160066570591).

Almost surely, 2^{130320133141181} is an apocalyptic number.

It is an amenable number.

130320133141181 is a deficient number, since it is larger than the sum of its proper divisors (1).

130320133141181 is an equidigital number, since it uses as much as digits as its factorization.

130320133141181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 130320133141181 in words is "one hundred thirty trillion, three hundred twenty billion, one hundred thirty-three million, one hundred forty-one thousand, one hundred eighty-one".