Base | Representation |
---|---|
bin | 11101101000011010111010… |
… | …010010001010110001010000 |
3 | 122002102120100011110101112110 |
4 | 131220122322102022301100 |
5 | 114040134423343120422 |
6 | 1141100352415225320 |
7 | 36310245303310011 |
oct | 3550327222126120 |
9 | 562376304411473 |
10 | 130321023020112 |
11 | 3858492103a711 |
12 | 12749106b18240 |
13 | 57942b19c8862 |
14 | 24277dd407008 |
15 | 100ee3770060c |
hex | 7686ba48ac50 |
130321023020112 has 80 divisors (see below), whose sum is σ = 344495562890688. Its totient is φ = 42429662499840.
The previous prime is 130321023020099. The next prime is 130321023020119. The reversal of 130321023020112 is 211020320123031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130321023020119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 244030378 + ... + 244563830.
Almost surely, 2130321023020112 is an apocalyptic number.
130321023020112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130321023020112 is an abundant number, since it is smaller than the sum of its proper divisors (214174539870576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130321023020112 is a wasteful number, since it uses less digits than its factorization.
130321023020112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 651868 (or 651862 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 130321023020112 its reverse (211020320123031), we get a palindrome (341341343143143).
The spelling of 130321023020112 in words is "one hundred thirty trillion, three hundred twenty-one billion, twenty-three million, twenty thousand, one hundred twelve".
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