Base | Representation |
---|---|
bin | 1011110110100100011011… |
… | …1001010101100011111111 |
3 | 1201010212011212100100100021 |
4 | 2331221012321111203333 |
5 | 3202004240233233321 |
6 | 43414512352113011 |
7 | 2513353042034446 |
oct | 275510671254377 |
9 | 51125155310307 |
10 | 13032120211711 |
11 | 4174989127207 |
12 | 1565866835767 |
13 | 736c01396c53 |
14 | 330a87c9bd5d |
15 | 178ede4bb941 |
hex | bda46e558ff |
13032120211711 has 2 divisors, whose sum is σ = 13032120211712. Its totient is φ = 13032120211710.
The previous prime is 13032120211619. The next prime is 13032120211729. The reversal of 13032120211711 is 11711202123031.
It is a strong prime.
It is an emirp because it is prime and its reverse (11711202123031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13032120211711 - 29 = 13032120211199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13032120211751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516060105855 + 6516060105856.
It is an arithmetic number, because the mean of its divisors is an integer number (6516060105856).
Almost surely, 213032120211711 is an apocalyptic number.
13032120211711 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032120211711 is an equidigital number, since it uses as much as digits as its factorization.
13032120211711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 13032120211711 its reverse (11711202123031), we get a palindrome (24743322334742).
The spelling of 13032120211711 in words is "thirteen trillion, thirty-two billion, one hundred twenty million, two hundred eleven thousand, seven hundred eleven".
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