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130321404332240 = 245112177310848473
BaseRepresentation
bin11101101000011011010001…
…000000110000100011010000
3122002102121022201222001102212
4131220123101000300203100
5114040141214002112430
61141100454320131252
736310260613356122
oct3550332100604320
9562377281861385
10130321404332240
1138584aa7301100
12127491b2766b28
1357943429c6034
142427837d05212
15100ee5ae21b95
hex7686d10308d0

130321404332240 has 240 divisors, whose sum is σ = 357468240349584. Its totient is φ = 43990987898880.

The previous prime is 130321404332237. The next prime is 130321404332261. The reversal of 130321404332240 is 42233404123031.

It can be written as a sum of positive squares in 8 ways, for example, as 28084149104704 + 102237255227536 = 5299448^2 + 10111244^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130321404332197 and 130321404332206.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6588644 + ... + 17437116.

Almost surely, 2130321404332240 is an apocalyptic number.

130321404332240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130321404332240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178734120174792).

130321404332240 is an abundant number, since it is smaller than the sum of its proper divisors (227146836017344).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130321404332240 is a wasteful number, since it uses less digits than its factorization.

130321404332240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10848598 (or 10848581 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 130321404332240 its reverse (42233404123031), we get a palindrome (172554808455271).

The spelling of 130321404332240 in words is "one hundred thirty trillion, three hundred twenty-one billion, four hundred four million, three hundred thirty-two thousand, two hundred forty".