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130323355517 is a prime number
BaseRepresentation
bin111100101011111100…
…0001001011101111101
3110110101110101102000002
41321113320021131331
54113400234334032
6135511505444045
712262351146545
oct1712770113575
9413343342002
10130323355517
11502a71559a3
1221311040625
13c39bb8c164
1464443dc325
1535cb437862
hex1e57e0977d

130323355517 has 2 divisors, whose sum is σ = 130323355518. Its totient is φ = 130323355516.

The previous prime is 130323355501. The next prime is 130323355531. The reversal of 130323355517 is 715553323031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119988803236 + 10334552281 = 346394^2 + 101659^2 .

It is a cyclic number.

It is not a de Polignac number, because 130323355517 - 24 = 130323355501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130323355567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65161677758 + 65161677759.

It is an arithmetic number, because the mean of its divisors is an integer number (65161677759).

Almost surely, 2130323355517 is an apocalyptic number.

It is an amenable number.

130323355517 is a deficient number, since it is larger than the sum of its proper divisors (1).

130323355517 is an equidigital number, since it uses as much as digits as its factorization.

130323355517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 141750, while the sum is 38.

Adding to 130323355517 its reverse (715553323031), we get a palindrome (845876678548).

The spelling of 130323355517 in words is "one hundred thirty billion, three hundred twenty-three million, three hundred fifty-five thousand, five hundred seventeen".