Search a number
-
+
130330003139957 is a prime number
BaseRepresentation
bin11101101000100011010001…
…100010100110110101110101
3122002110102112000010202002202
4131220203101202212311311
5114040311321300434312
61141104435450314245
736311013655131305
oct3550432142466565
9562412460122082
10130330003139957
113858870a092665
121274a9b2428985
1357950b330813a
142428011d25605
1510102b0ca19c2
hex7688d18a6d75

130330003139957 has 2 divisors, whose sum is σ = 130330003139958. Its totient is φ = 130330003139956.

The previous prime is 130330003139857. The next prime is 130330003139969. The reversal of 130330003139957 is 759931300033031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129576650314276 + 753352825681 = 11383174^2 + 867959^2 .

It is a cyclic number.

It is not a de Polignac number, because 130330003139957 - 228 = 130329734704501 is a prime.

It is a super-2 number, since 2×1303300031399572 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130330003139857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65165001569978 + 65165001569979.

It is an arithmetic number, because the mean of its divisors is an integer number (65165001569979).

Almost surely, 2130330003139957 is an apocalyptic number.

It is an amenable number.

130330003139957 is a deficient number, since it is larger than the sum of its proper divisors (1).

130330003139957 is an equidigital number, since it uses as much as digits as its factorization.

130330003139957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 688905, while the sum is 47.

The spelling of 130330003139957 in words is "one hundred thirty trillion, three hundred thirty billion, three million, one hundred thirty-nine thousand, nine hundred fifty-seven".