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1303310144153 is a prime number
BaseRepresentation
bin10010111101110011010…
…101101001001010011001
311121121001220222012100202
4102331303111221022121
5132323134344103103
62434422111311545
7163106145303413
oct22756325511231
94547056865322
101303310144153
11462804665516
1219070bb1b5b5
1395b94b1bb14
144711b0459b3
1523d7e82d988
hex12f73569299

1303310144153 has 2 divisors, whose sum is σ = 1303310144154. Its totient is φ = 1303310144152.

The previous prime is 1303310144083. The next prime is 1303310144203. The reversal of 1303310144153 is 3514410133031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 681306620569 + 622003523584 = 825413^2 + 788672^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303310144153 - 28 = 1303310143897 is a prime.

It is a super-2 number, since 2×13033101441532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1303310144053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651655072076 + 651655072077.

It is an arithmetic number, because the mean of its divisors is an integer number (651655072077).

Almost surely, 21303310144153 is an apocalyptic number.

It is an amenable number.

1303310144153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303310144153 is an equidigital number, since it uses as much as digits as its factorization.

1303310144153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1303310144153 its reverse (3514410133031), we get a palindrome (4817720277184).

The spelling of 1303310144153 in words is "one trillion, three hundred three billion, three hundred ten million, one hundred forty-four thousand, one hundred fifty-three".