Base | Representation |
---|---|
bin | 10010111101110011010… |
… | …101101001001010011001 |
3 | 11121121001220222012100202 |
4 | 102331303111221022121 |
5 | 132323134344103103 |
6 | 2434422111311545 |
7 | 163106145303413 |
oct | 22756325511231 |
9 | 4547056865322 |
10 | 1303310144153 |
11 | 462804665516 |
12 | 19070bb1b5b5 |
13 | 95b94b1bb14 |
14 | 4711b0459b3 |
15 | 23d7e82d988 |
hex | 12f73569299 |
1303310144153 has 2 divisors, whose sum is σ = 1303310144154. Its totient is φ = 1303310144152.
The previous prime is 1303310144083. The next prime is 1303310144203. The reversal of 1303310144153 is 3514410133031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 681306620569 + 622003523584 = 825413^2 + 788672^2 .
It is a cyclic number.
It is not a de Polignac number, because 1303310144153 - 28 = 1303310143897 is a prime.
It is a super-2 number, since 2×13033101441532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1303310144053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651655072076 + 651655072077.
It is an arithmetic number, because the mean of its divisors is an integer number (651655072077).
Almost surely, 21303310144153 is an apocalyptic number.
It is an amenable number.
1303310144153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303310144153 is an equidigital number, since it uses as much as digits as its factorization.
1303310144153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 1303310144153 its reverse (3514410133031), we get a palindrome (4817720277184).
The spelling of 1303310144153 in words is "one trillion, three hundred three billion, three hundred ten million, one hundred forty-four thousand, one hundred fifty-three".
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