Base | Representation |
---|---|
bin | 1011110110101000000111… |
… | …1001100101001110011011 |
3 | 1201010221201212001111011021 |
4 | 2331222001321211032123 |
5 | 3202013302143202421 |
6 | 43415154513343311 |
7 | 2513416422153343 |
oct | 275520171451633 |
9 | 51127655044137 |
10 | 13033110131611 |
11 | 4175346995729 |
12 | 1565aa2267b37 |
13 | 73702b4b4c7b |
14 | 330b3d543d23 |
15 | 17904b35b341 |
hex | bda81e6539b |
13033110131611 has 2 divisors, whose sum is σ = 13033110131612. Its totient is φ = 13033110131610.
The previous prime is 13033110131603. The next prime is 13033110131617. The reversal of 13033110131611 is 11613101133031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13033110131611 - 23 = 13033110131603 is a prime.
It is not a weakly prime, because it can be changed into another prime (13033110131617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516555065805 + 6516555065806.
It is an arithmetic number, because the mean of its divisors is an integer number (6516555065806).
Almost surely, 213033110131611 is an apocalyptic number.
13033110131611 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033110131611 is an equidigital number, since it uses as much as digits as its factorization.
13033110131611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
Adding to 13033110131611 its reverse (11613101133031), we get a palindrome (24646211264642).
The spelling of 13033110131611 in words is "thirteen trillion, thirty-three billion, one hundred ten million, one hundred thirty-one thousand, six hundred eleven".
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