Base | Representation |
---|---|
bin | 1011110110101000001100… |
… | …1101000010101100011011 |
3 | 1201010221210101020001000212 |
4 | 2331222003031002230123 |
5 | 3202013323243312032 |
6 | 43415201014321335 |
7 | 2513420106135455 |
oct | 275520315025433 |
9 | 51127711201025 |
10 | 13033132010267 |
11 | 4175358279466 |
12 | 1565aa965924b |
13 | 737032ba5515 |
14 | 330b423db2d5 |
15 | 17904d22dbb2 |
hex | bda83342b1b |
13033132010267 has 2 divisors, whose sum is σ = 13033132010268. Its totient is φ = 13033132010266.
The previous prime is 13033132010207. The next prime is 13033132010323. The reversal of 13033132010267 is 76201023133031.
13033132010267 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13033132010267 - 220 = 13033130961691 is a prime.
It is a super-2 number, since 2×130331320102672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13033132010207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516566005133 + 6516566005134.
It is an arithmetic number, because the mean of its divisors is an integer number (6516566005134).
Almost surely, 213033132010267 is an apocalyptic number.
13033132010267 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033132010267 is an equidigital number, since it uses as much as digits as its factorization.
13033132010267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 32.
Adding to 13033132010267 its reverse (76201023133031), we get a palindrome (89234155143298).
The spelling of 13033132010267 in words is "thirteen trillion, thirty-three billion, one hundred thirty-two million, ten thousand, two hundred sixty-seven".
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