Base | Representation |
---|---|
bin | 1011110110101000001100… |
… | …1101000010101101010011 |
3 | 1201010221210101020001002221 |
4 | 2331222003031002231103 |
5 | 3202013323243312243 |
6 | 43415201014321511 |
7 | 2513420106135565 |
oct | 275520315025523 |
9 | 51127711201087 |
10 | 13033132010323 |
11 | 4175358279507 |
12 | 1565aa9659297 |
13 | 737032ba5559 |
14 | 330b423db335 |
15 | 17904d22dbed |
hex | bda83342b53 |
13033132010323 has 2 divisors, whose sum is σ = 13033132010324. Its totient is φ = 13033132010322.
The previous prime is 13033132010267. The next prime is 13033132010333. The reversal of 13033132010323 is 32301023133031.
13033132010323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13033132010323 - 29 = 13033132009811 is a prime.
It is not a weakly prime, because it can be changed into another prime (13033132010333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516566005161 + 6516566005162.
It is an arithmetic number, because the mean of its divisors is an integer number (6516566005162).
Almost surely, 213033132010323 is an apocalyptic number.
13033132010323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033132010323 is an equidigital number, since it uses as much as digits as its factorization.
13033132010323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 13033132010323 its reverse (32301023133031), we get a palindrome (45334155143354).
The spelling of 13033132010323 in words is "thirteen trillion, thirty-three billion, one hundred thirty-two million, ten thousand, three hundred twenty-three".
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