Base | Representation |
---|---|
bin | 111100101100001011… |
… | …0110101101110001001 |
3 | 110110102000112011110112 |
4 | 1321120112311232021 |
5 | 4113404314313342 |
6 | 135512354124105 |
7 | 12262506426212 |
oct | 1713026655611 |
9 | 413360464415 |
10 | 130331401097 |
11 | 50300750737 |
12 | 21313880635 |
13 | c3a0748261 |
14 | 64454d4409 |
15 | 35cbec6682 |
hex | 1e585b5b89 |
130331401097 has 2 divisors, whose sum is σ = 130331401098. Its totient is φ = 130331401096.
The previous prime is 130331401093. The next prime is 130331401117. The reversal of 130331401097 is 790104133031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130323888016 + 7513081 = 361004^2 + 2741^2 .
It is a cyclic number.
It is not a de Polignac number, because 130331401097 - 22 = 130331401093 is a prime.
It is a super-2 number, since 2×1303314010972 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130331401093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65165700548 + 65165700549.
It is an arithmetic number, because the mean of its divisors is an integer number (65165700549).
Almost surely, 2130331401097 is an apocalyptic number.
It is an amenable number.
130331401097 is a deficient number, since it is larger than the sum of its proper divisors (1).
130331401097 is an equidigital number, since it uses as much as digits as its factorization.
130331401097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 32.
The spelling of 130331401097 in words is "one hundred thirty billion, three hundred thirty-one million, four hundred one thousand, ninety-seven".
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